Description
请定义具有red, orange, yellow, green, blue, violet六种颜色的枚举类型color,根据输入的颜色名称,输出以下六种植物花朵的颜色:
Rose(red), Poppies(orange), Sunflower(yellow), Grass(green), Bluebells(blue), Violets(violet)。如果输入的颜色名称不在枚举类型color中,例如输入purple,请输出I don’t know about the color purple.
Input
输入数据有多行,每行有一个字符串代表颜色名称,颜色名称最多30个字符,直到文件结束为止。
Output
输出对应颜色的植物名称,例如:Bluebells are blue. 如果输入的颜色名称不在枚举类型color中,例如purple, 请输出I don’t know about the color purple.
Sample
Input
blue
yellow
purple
Output
Bluebells are blue.
Sunflower are yellow.
I don’t know about the color purple.
Hint
枚举简单但是操作复杂,只需要与已有数据一一对比,找到相对应的数据
#include <stdio.h>
#include <string.h>
enum color{red,orange,yellow,green,blue,violet,no}w;
int main()
{
char a[31];
while(gets(a))
{
if(strcmp(a,"red")==0)
w=red;
else if(strcmp(a,"orange")==0)
w=orange;
else if(strcmp(a,"yellow")==0)
w=yellow;
else if(strcmp(a,"green")==0)
w=green;
else if(strcmp(a,"blue")==0)
w=blue;
else if(strcmp(a,"violet")==0)
w=violet;
else w = no;
switch(w)
{
case red:printf("Rose are red.\n");break;
case orange:printf("Poppies are orange.\n");break;
case yellow:printf("Sunflower are yellow.\n");break;
case green:printf("Grass are green.\n");break;
case blue:printf("Bluebells are blue.\n");break;
case violet:printf("Violets are violet.\n");break;
case no:
printf("I don't know about the color %s.\n",a);
}
}
return 0;
}