代码与思路

#include <cstdio>
using namespace std;

#define INF 0x7fffffff

int main(){
	int num, cost, diamonds[100010];
	scanf("%d%d", &num, &cost);
	for(int i = 0; i < num; i++)
		scanf("%d", &diamonds[i]);

	//left,right用来标记要输出的左右边界
	//right=-1是为了操作的统一
	//sum用来求left到right的数的和
	//min用来记录目前大于cost的最小sum
	int left = 0, right = -1, sum = 0, min = INF;
	//第一遍循环确认min
	while(true){	
		if(sum == cost){
			min = cost;
			break;
		}
		else if(sum < cost){
			if(right + 1 < num)
				sum += diamonds[++right];
			else
				break;
		}
		else{
			min = sum < min ? sum : min;
			sum -= diamonds[left++];
		}
	}
	left = 0;right = -1;sum = 0;
	//第二遍循环输出所有满足条件的left和right
	while(true){
		if(sum == min){
			printf("%d-%d\n", left + 1, right + 1);
			sum -= diamonds[left++];
		}
		else if(sum < min){
			if(right + 1 < num)
				sum += diamonds[++right];
			else
				break;
		}
		else
			sum -= diamonds[left++];
	}
	
	return 0;
}