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Codeforces Round #617 (Div. 3) D. Fight with Monsters
其他
2020-02-09 22:00:57
阅读次数: 0
题意:打怪,拿分,不同就是可以让别人跳过打怪哪一个环节,不过只有k次
题解:算出每个怪消耗的k,排序 ,贪心
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转载自
www.cnblogs.com/RE-TLE/p/12288935.html
Codeforces Round #617 (Div. 3) D. Fight with Monsters
Codeforces Round #617 (Div. 3) D Fight with Monsters(贪心)
Codeforces Round #617 (Div. 3), problem: (D) Fight with Monsters 【贪心博弈】
Codeforces Round #617 (Div. 3) A~D
Codeforces Round #617 (Div. 3)(A~D)
【寒假CodeForces】D. Fight with Monsters 题解
codeforce div3 d Fight with Monsters
Codeforces Round #617 (Div. 3) A、B、C、D、E
Codeforces Round #617 (Div. 3)
Codeforces Round #617 (Div. 3)题解
Codeforces Round #617 (Div. 3) 题解
Codeforces Round #617 (Div. 3)(题解)
Codeforces Round #617 (Div. 3) (A ~ F)
Codeforces Round #617 (Div. 3) Editorial
D. Fight with Monsters
【题解】Codeforces Round #617 (Div. 3) A、B、C、D、E、F
Fight with Monsters CodeForces - 1296D
CodeForces - 1296D Fight with Monsters
Codeforces 1296D Fight with Monsters(贪心)
codeforces 1296D Fight with Monsters 贪心
Codeforces Round #617 (Div. 3)B. Food Buying
题解Codeforces Round #617 (Div. 3) (CF1296)
Codeforces Round #617 (Div. 3)A. Array with Odd Sum
Codeforces Round #617 (Div. 3) B. Food Buying
Codeforces Round #617 (Div. 3) A. Array with Odd Sum
Codeforces Round #617 (Div. 3)(A~E2)
Codeforces Round #617 (Div. 3) F. Berland Beauty
Codeforces Round #617 (Div. 3) A-E2题解
Codeforces Round #506 (Div. 3) D. Concatenated Multiples
Codeforces Round #515 (Div. 3) D. Boxes Packing
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