#@ 1 - 正常执行的mysql 语句为:
select * from RESIDENTIAL_AREA where RA_ID like 'HF-%'
#@ 2 - 在python 代码中为: 最后面的那个 % 需要4个% 去代替(raid = HF-)
select_sql = ''' select * from RESIDENTIAL_AREA where RA_ID
like '%s%%%%' ''' % (raid)
#@ 3 - python 代码中 输出结果为:print(select_sql)
select * from RESIDENTIAL_AREA where RA_ID like 'HF-%%'
python 中写mysql 关于 like % 问题
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转载自blog.csdn.net/wang603603/article/details/86540996
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