二分法搜索python实现以及分析

#!/usr/bin/env python3
# -*- coding: utf-8 -*-
def binaray_search(list, item):
	low = 0
	high = len(list) - 1
	i = 0
	while(low <= high):	
		mid = (low + high)/2
		guess = mid
		if guess == item:
			i= i + 1
			print('got it!')
			return guess,i
			
		elif guess < item:
			low  = mid + 1
			i= i + 1
		else:
			high = mid - 1
			i= i + 1
	return 'no match', i
	
if __name__ == '__main__':
	my_list = [1,2,3,4,5,6,7,8,9,10, 11,12]
	my_item = 13	
	a = binaray_search(my_list, my_item)[0]
	i= binaray_search(my_list, my_item)[1]
	print (i)
	if a == 'no match':
		print('no answer')
	else:
		print('to_fine_num is : %d, take %d times to find' %(a, i))
	
	
  1. 以上是python实现二分法搜索的代码,对于长度为2^n的list,最多需要n次即可确定目标,时间复杂度为O(logn).
  2. 前提:查找的list必须有序。

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转载自blog.csdn.net/u014180553/article/details/79532955