HDU 1850 - Being a Good Boy in Spring Festival

Nimm博弈,需要统计可行方案的个数。

代码如下:

#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
using namespace std;
int ways[102];
int main()
{
#ifdef test
    freopen("input.txt", "r", stdin);
#endif
    int m;
    while(scanf("%d", &m) && m!=0)
    {
        int sum = 0;
        for(int i=0; i<m; ++i)
        {
            scanf("%d", &ways[i]);
            sum ^= ways[i];
        }
        if(sum == 0)
            printf("0\n");
        else
        {
            int ans = 0;
            for(int i=0; i<m; ++i)
                if(ways[i] > (sum^ways[i]))// 关键
                    ++ans;
            printf("%d\n", ans);
        }
    }
    return 0;
}


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转载自blog.csdn.net/GooMaple/article/details/8883541