def findSubArraySum(array,target):
for i in range(len(array)):
temp=0
for j in range(i,len(array)):
temp+=array[j]
if temp<target:
continue
elif temp==target:
for k in range(i,j+1):
print(array[k])
else:
break
if __name__=="__main__":
array=[1,2,4,7,8,9]
target=7
findSubArraySum(array,target)
python实现----查找数组中连续元素的和等于给定数的子数组
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转载自blog.csdn.net/haoshan4783/article/details/88681174
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