链接:https://ac.nowcoder.com/acm/contest/549/I
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstring>
using namespace std;
int main(){
int n,k,a[100005],s,num;
cin>>n>>k;
s = 0;
for(int i = 0;i<n;++i){
scanf("%d",&a[i]);
s ^= a[i];
}
if(s != 0) cout<<"YES\n";
else{
num = 0;
for(int i = 0;i<n;++i){
if(a[i] < k) continue; //必须正好取k个
s = num^a[i]; //这里用到a^a = 0这个性质
s ^= (a[i]-k);
if(s != 0){
cout<<"YES\n";
return 0;
}
}
cout<<"NO\n";
}
return 0;
}