思路:100和为5050,100平方和(根据立方)得出公式
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main(){
int sum1=0,sum2=0;
sum1=5050;
sum2=(2*(100*100*100)+3*(100*100)+100)/6;
printf("%d\n",sum1*sum1-sum2);
return 0;
}
思路:100和为5050,100平方和(根据立方)得出公式
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
int main(){
int sum1=0,sum2=0;
sum1=5050;
sum2=(2*(100*100*100)+3*(100*100)+100)/6;
printf("%d\n",sum1*sum1-sum2);
return 0;
}