畅通工程浅析

畅通工程:
这道题主要是考察并查集的知识
程序如下:

#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
int pre[1010];
int zhao(int root)//查找根结点
{
    
    
	int son, tmp;
	son = root;
	while(root != pre[root]) 
		root = pre[root];
	while(son != root) //路径压缩,将此路径中的每一个元素的直系上司都变为最高的root
	{
    
    
		tmp = pre[son];
		pre[son] = root;
		son = tmp;
	}
	return root; 
}

int main()
{
    
    
	int num, road, total, i, start, end1, root1, root2;
	while(scanf("%d%d", &num, &road) && num)
	{
    
    
		total = num - 1; //最少可以的路数
		for(i = 1; i <= num; ++i) 
			pre[i] = i;
		while(road--)
		{
    
    
			scanf("%d%d", &start, &end1); 
			root1 = zhao(start);
			root2 = zhao(end1);
			if(root1 != root2)
			{
    
    
				pre[root1] = root2;
				total--;(要建的路)就少一个
			}
		}
		printf("%d\n", total);
	}
	return 0;
}

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转载自blog.csdn.net/malloch/article/details/105935098