A + B Problem Too问题
水题,不多说先上题目
题目
This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Time limit | Memory limit | OS | Source |
---|---|---|---|
1000 ms | 32768 kB | Windows | HDU 2007-6 Programming Contest |
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Example
input | output |
---|---|
1 1 | no |
8600 8600 | yes |
问题链接:HDU - 2101
问题描述
输入两个数据,求它们的和,并判断和能不能被86整除,如果能就输出yes,不能则输出no。
问题分析
首先获得用户的两个输入,然后求两数的和,将和存于一变量中,然后再用该变量除以86求余数,如果余数得0则输出yes,其他数则输出no。在其外套上一层while循环用于重复程序。
AC通过的C++语言程序代码如下:
#include<iostream>
using namespace std;
int main()
{
int a, b, r;
while (cin >> a >> b)
{
r = a + b;
if (r % 86 == 0)
cout << "yes" << endl;
else
cout << "no" << endl;
}
}