This problem is also a A + B problem,but it has a little
difference,you should determine does (a+b) could be divided with
86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in
one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes
程序分析:while循环来多次输入,if判断(a+b)是否为86的倍数,!!程序要求换行!!
AC通过程序:
#include<stdio.h>
int main()
{
int a,b;
while(scanf("%d %d",&a,&b)!=EOF)
{
if((a+b)%86==0)
{
printf("yes\n");
}else printf("no\n");
}
return 0;
}
小小改进后:
#include<stdio.h>
int main()
{
int a,b;
while(scanf("%d %d",&a,&b)!=EOF)
(a+b)%86==0?printf("yes\n"):printf("no\n");
return 0;
}