This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes
题目说明：
输入两个数A和B，判断他们的和能否被86整除，若可以，则输出“yes”，否则输出“no”。
程序说明：
用cin>>a>>b作为while（）的参数，可以实现多次输入数据的要求，while（）函数内执行if判断语句，看A+B能否被86整除。
程序实现：
#include <iostream>
using namespace std;
int main()
{
int a, b;
while (cin >> a >> b)
{
if ((a+b)%86)
cout << "no" << endl;
else
cout << "yes" << endl;
}
}