Text Reverse
Time limit 1000 ms
Memory limit 32768 kB
OS Windows
Source HDU 2007-6 Programming Contest
Problem Description
This problem is also a A + B problem,but it has a little difference,you should determine does (a+b) could be divided with 86.For example ,if (A+B)=98,you should output no for result.
Input
Each line will contain two integers A and B. Process to end of file.
Output
For each case, if(A+B)%86=0,output yes in one line,else output no in one line.
Sample Input
1 1
8600 8600
Sample Output
no
yes
问题链接:HDU - 1000
问题简述:
计算A+B,判断能否被86整除,若能输出“yes”,否则输出“no”。
问题分析:
判断整除
程序说明:
输入a,b两个整型数值,然后相加,判断是否能被86整除,若能输出“yes”,否则输出“no”。
#include<iostream>
using namespace std;
int main()
{
int a, b;
while (cin >> a >> b)
{
if ((a + b) % 86==0)
cout << "yes" << endl;
else
cout << "no" << endl;
}
return 0;
}